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Products and integration by parts

Integral of eˣ sin x: Formula, Steps and Examples

The integral of eˣ sin x is ½eˣ(sin x − cos x) + C. Learn the integrate-twice-and-solve trick, a check, a graph and the e^(ax) sin(bx) formula.

Products and integration by parts Updated 3 min read

At a glance

\int e^x\sin x\,dx = \frac{e^x}{2}\left(\sin x - \cos x\right) + C
Antiderivative
\frac{1}{2}e^x(\sin x - \cos x) + C
Method
Integration by parts twice, then solve for the integral
Companion
\int e^x\cos x\,dx = \frac{1}{2}e^x(\sin x + \cos x) + C
General form
\int e^{ax}\sin bx\,dx = \frac{e^{ax}(a\sin bx - b\cos bx)}{a^2 + b^2} + C
From 0 to π
\frac{e^\pi + 1}{2} \approx 12.07
On this page
  1. Graph of eˣ sin x
  2. How to integrate eˣ sin x step by step
  3. Check by differentiating
  4. The general formula
  5. Definite integrals
  6. Worked examples
  7. Common mistakes

The integral of e^x\sin x is \dfrac{1}{2}e^x(\sin x - \cos x) + C. It is the famous "loop" integral: integration by parts never finishes on its own, but after two steps you can solve for the answer with algebra.

\int e^x\sin x\,dx = \frac{e^x}{2}\left(\sin x - \cos x\right) + C

Graph of eˣ sin x

y = eˣ sin x with the area from 0 to π shaded
The shaded area is \frac{e^\pi + 1}{2} \approx 12.07. The curve oscillates like \sin x, but the swings grow because of the e^x factor.

How to integrate eˣ sin x step by step

Call the integral I. Use integration by parts with the trig function as u both times.

  1. First pass. u = \sin x, dv = e^x\,dx, so du = \cos x\,dx and v = e^x: I = e^x\sin x - \int e^x\cos x\,dx
  2. Second pass, on \int e^x\cos x\,dx. Again the trig function is u: u = \cos x, dv = e^x\,dx, so du = -\sin x\,dx, v = e^x: \int e^x\cos x\,dx = e^x\cos x + \int e^x\sin x\,dx = e^x\cos x + I
  3. Substitute back. The original integral has returned: I = e^x\sin x - e^x\cos x - I
  4. Solve for I. Add I to both sides: 2I = e^x(\sin x - \cos x), so I = \frac{e^x}{2}(\sin x - \cos x) + C

The + C is added at the end, after solving. It works just as well with u = e^x both times. What fails is switching: if you take u = \sin x first and u = e^x second, the second step undoes the first and you get I = I.

Check by differentiating

\frac{d}{dx}\left[\frac{e^x}{2}(\sin x - \cos x)\right] = \frac{e^x}{2}(\sin x - \cos x) + \frac{e^x}{2}(\cos x + \sin x) = \frac{e^x}{2}\cdot 2\sin x = e^x\sin x

The general formula

The same two-step loop for e^{ax}\sin bx and e^{ax}\cos bx gives

\int e^{ax}\sin bx\,dx = \frac{e^{ax}(a\sin bx - b\cos bx)}{a^2 + b^2} + C
\int e^{ax}\cos bx\,dx = \frac{e^{ax}(a\cos bx + b\sin bx)}{a^2 + b^2} + C

With a = b = 1 the denominator is 2, matching the result above.

A quicker route with complex numbers. Since e^{ix} = \cos x + i\sin x, e^x\sin x is the imaginary part of e^{(1+i)x}. Integrating gives \frac{e^{(1+i)x}}{1+i} = \frac{(1-i)}{2}e^x(\cos x + i\sin x), whose imaginary part is \frac{e^x}{2}(\sin x - \cos x).

Definite integrals

From 0 to π:

\left[\frac{e^x}{2}(\sin x - \cos x)\right]_0^\pi = \frac{e^\pi}{2}(0 + 1) - \frac{1}{2}(0 - 1) = \frac{e^\pi + 1}{2} \approx 12.07

From 0 to π/2: \frac{e^{\pi/2}}{2}(1 - 0) - \frac{1}{2}(0 - 1) = \frac{e^{\pi/2} + 1}{2} \approx 2.905.

Decaying version. \int_0^\infty e^{-x}\sin x\,dx. Use the formula with a = -1, b = 1: the antiderivative is \frac{e^{-x}(-\sin x - \cos x)}{2}, which goes to 0 at infinity. So the value is 0 - \left(-\frac{1}{2}\right) = \frac{1}{2}.

Worked examples

Example 1: eˣ cos x. From step 2 above, \int e^x\cos x\,dx = e^x\cos x + I. Substitute I:

\int e^x\cos x\,dx = e^x\cos x + \frac{e^x}{2}(\sin x - \cos x) = \frac{e^x}{2}(\sin x + \cos x) + C

Example 2: different rates. \int e^{2x}\sin 3x\,dx = \frac{e^{2x}(2\sin 3x - 3\cos 3x)}{13} + C, using a^2 + b^2 = 4 + 9 = 13.

Example 3: damped vibration. A spring's displacement is e^{-t}\cos t. Its total signed displacement over [0, \infty) is \int_0^\infty e^{-t}\cos t\,dt = \frac{1}{2}, from the cosine formula with a = -1, b = 1: the antiderivative \frac{e^{-t}(\sin t - \cos t)}{2} goes from -\frac{1}{2} to 0.

Common mistakes

  1. Switching the choice of u between the two passes. You end up with I = I, which is true but useless.
  2. Forgetting to divide by 2. After step 3 you have 2I, not I.
  3. Sign errors in the second pass. \frac{d}{dx}\cos x = -\sin x, so the second integral is added, not subtracted.
  4. Expecting parts to terminate. With x\sin x the power of x drops away; with e^x\sin x nothing drops away, so you need the loop. Compare the integral of x sin x.

The repeated parts and LIATE lesson practices this loop, and the integration by parts guide has more examples.

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Repeated parts and LIATE

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Frequently asked questions

What is the integral of eˣ sin x?

It is \frac{1}{2}e^x(\sin x - \cos x) + C.

What is the integral of eˣ cos x?

It is \frac{1}{2}e^x(\sin x + \cos x) + C. The same two-step method works, with the sign of the cosine term flipped.

Why does integration by parts not end for eˣ sin x?

Neither e^x nor \sin x becomes simpler when differentiated, so parts keeps cycling. After two steps the original integral reappears, and you solve the equation I = \text{stuff} - I for I.

What is the integral of e^(2x) sin(3x)?

It is \frac{e^{2x}(2\sin 3x - 3\cos 3x)}{13} + C, from the general formula with a = 2 and b = 3.

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