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AP Calc BC Unit 9 Review: Parametric, Polar and Vectors

AP Calculus BC Unit 9 review: parametric derivatives and arc length, vector-valued motion, polar slopes and polar area, with sample questions and practice.

AP Calculus units Updated 4 min read

At a glance

AB exam weight
Not on the AB exam
BC exam weight
10–15%
Big ideas
Parametric derivatives, arc length, motion in the plane, polar area
BC only
The whole unit
Comes before
Unit 10, infinite sequences and series
On this page
  1. What Unit 9 covers
  2. The key ideas
  3. Sample questions
  4. How to study Unit 9

AP Calculus Unit 9, Parametric Equations, Polar Coordinates, and Vector-Valued Functions, is the first of the two BC-only units. It takes derivatives and integrals off the x-axis and into the plane: a particle moving along a path, a curve given by its angle and distance from the origin, a position written as a vector. The calculus is the same. What changes is how you set it up.

AP Calculus AB AP Calculus BC
Exam weight not on the AB exam 10–15% (BC only)
Extra topics none the whole unit is BC only

What Unit 9 covers

College Board splits the unit into these topics. Each row links to a lesson where you can practice it with new numbers every time.

Topic What you learn Practice
Parametric equations Slopes \frac{dy}{dx} = \frac{dy/dt}{dx/dt} and tangent lines Parametric curves
Second derivatives of parametric equations Concavity of a parametric curve Parametric curves
Arc length of parametric curves \int_a^b \sqrt{(x')^2 + (y')^2}\,dt Parametric arc length
Vector-valued functions Differentiating \langle x(t), y(t)\rangle Parametric motion
Integrating vector-valued functions Position from velocity, component by component Parametric motion
Motion in the plane Velocity, speed, acceleration and distance traveled Parametric motion
Polar coordinates and differentiation Converting, and slopes of polar curves Polar slopes
Area of a polar region \frac{1}{2}\int r^2\,d\theta for one curve Polar area
Area between two polar curves Outer squared minus inner squared Polar area

The key ideas

A parametric curve is a path traced over time. Both x and y depend on a parameter t. The slope is a ratio of rates:

\frac{dy}{dx} = \frac{dy/dt}{dx/dt}, \qquad \frac{d^2y}{dx^2} = \frac{\frac{d}{dt}\left(\frac{dy}{dx}\right)}{dx/dt}
The parametric circle x = 2cos t, y = 2sin t
As t goes from 0 to 2\pi the point traces the circle x^2 + y^2 = 4 once, counterclockwise. Its arc length from t = 0 to t = \pi is 2\pi.

Vectors bundle motion together. If position is \vec{r}(t) = \langle x(t), y(t)\rangle, then velocity is \vec{v}(t) = \langle x'(t), y'(t)\rangle and acceleration is \vec{a}(t) = \langle x''(t), y''(t)\rangle. Speed is the length of the velocity vector, and total distance is the integral of speed.

Polar curves use angle and distance. A point is (r, \theta) with x = r\cos\theta and y = r\sin\theta. For slopes, differentiate x and y with respect to \theta and divide. For area, add up thin sectors:

A = \frac{1}{2}\int_\alpha^\beta r^2\,d\theta

Sample questions

1. Parametric slope and concavity. For x = t^2 and y = t^3 - 3t:

\frac{dy}{dx} = \frac{3t^2 - 3}{2t} = \frac{3}{2}\left(t - \frac{1}{t}\right)

At t = 2 the slope is \frac{9}{4}. The curve has horizontal tangents at t = \pm 1. For concavity, \frac{d}{dt}\left(\frac{dy}{dx}\right) = \frac{3}{2}\left(1 + \frac{1}{t^2}\right), so at t = 2:

\frac{d^2y}{dx^2} = \frac{\frac{3}{2}\cdot\frac{5}{4}}{4} = \frac{15}{32}

2. Parametric arc length. For x = 2\cos t and y = 2\sin t on [0, \pi], (x')^2 + (y')^2 = 4\sin^2 t + 4\cos^2 t = 4, so the length is \int_0^\pi 2\,dt = 2\pi, half the circumference of a circle of radius 2.

3. Motion in the plane. A particle has position \vec{r}(t) = \langle t^2, 3t\rangle. Then \vec{v}(t) = \langle 2t, 3\rangle and \vec{a}(t) = \langle 2, 0\rangle. At t = 2 the speed is \sqrt{4^2 + 3^2} = 5.

4. Polar area. The area inside the cardioid r = 1 + \cos\theta is

\frac{1}{2}\int_0^{2\pi} (1 + \cos\theta)^2\,d\theta = \frac{1}{2}\left(2\pi + 0 + \pi\right) = \frac{3\pi}{2}

using \int_0^{2\pi}\cos\theta\,d\theta = 0 and \int_0^{2\pi}\cos^2\theta\,d\theta = \pi.

How to study Unit 9

  • Divide by \frac{dx}{dt} twice. It appears in the first derivative and again in the second. Leaving it out of \frac{d^2y}{dx^2} is the most common Unit 9 mistake.
  • Treat vectors one component at a time. Differentiate, integrate and add initial positions for x and y separately.
  • Find polar intersections first. For the area between two polar curves, set the r values equal to get the \theta limits, then use \frac{1}{2}\int \left(r_{\text{outer}}^2 - r_{\text{inner}}^2\right)d\theta.
  • Use your calculator where allowed. Many polar and arc length integrals have no simple antiderivative, so they appear on the calculator section.
  • Work through problem sets. Try the parametric and polar practice problems, each with full solutions.

For the full course map, see the AP Calculus BC guide, or compare the two courses in the AP Calculus AB guide.

AP and Advanced Placement are registered trademarks of College Board, which is not affiliated with PracticeCalculus and does not endorse this guide. Unit names and weights come from College Board's course framework; check it for any changes.

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Frequently asked questions

What is AP Calculus Unit 9 about?

Unit 9 extends calculus to curves that are not graphs of y = f(x). You find first and second derivatives and arc length for parametric curves, analyze motion with vector-valued functions, and find slopes and areas for curves in polar coordinates.

Is Unit 9 on the AP Calculus AB exam?

No. Unit 9 is only in AP Calculus BC, where it is 10 to 15 percent of the multiple-choice score. It also appears on the free-response section, usually as a particle moving in the plane or a polar region.

What is the hardest part of Unit 9?

The parametric second derivative and polar area. For \frac{d^2y}{dx^2}, many students forget to divide by \frac{dx}{dt}. For polar area, the common mistakes are forgetting the \frac{1}{2} and using the wrong \theta limits.

Do I need to convert polar curves to rectangular form?

Sometimes. Use x = r\cos\theta and y = r\sin\theta to find slopes of polar curves. For area, stay in polar form and use \frac{1}{2}\int r^2\,d\theta.

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