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Derivative rules

Chain Rule for Derivatives: Formula, Examples and Common Forms

The chain rule: the derivative of f(g(x)) is f'(g(x))·g'(x). The formula in both notations, a table of common forms, worked examples and mistakes.

Derivative rules Updated 2 min read

At a glance

\frac{d}{dx}\,f(g(x)) = f'(g(x))\,g'(x)
Applies to
Compositions, a function inside another function
In words
Derivative of the outside (inside left alone) times the derivative of the inside
Leibniz form
\frac{dy}{dx} = \frac{dy}{du} \cdot \frac{du}{dx}
Spot it
Anything other than plain x inside a power, root, trig, exponential or log
Integral version
U-substitution
On this page
  1. The chain rule formula
  2. Common chain rule forms
  3. Worked examples
  4. How to spot a composition
  5. Common mistakes

The chain rule differentiates a composition, one function inside another. You take the derivative of the outer function, leave the inner function alone, and multiply by the derivative of the inner function. Almost every non-trivial derivative uses it.

The chain rule formula

If g is differentiable at x and f is differentiable at g(x), then

\frac{d}{dx}\,f(g(x)) = f'(g(x))\,g'(x)

In Leibniz notation, with y = f(u) and u = g(x):

\frac{dy}{dx} = \frac{dy}{du} \cdot \frac{du}{dx}

Think of rates multiplying: if y changes 3 times as fast as u, and u changes 2 times as fast as x, then y changes 3 \cdot 2 = 6 times as fast as x.

Common chain rule forms

Here u is any differentiable function of x and u' is its derivative.

Function Derivative
u^n n\,u^{n-1}\,u'
\sqrt{u} \frac{u'}{2\sqrt{u}}
e^u e^u\,u'
\ln u \frac{u'}{u}
\sin u \cos u \cdot u'
\cos u -\sin u \cdot u'
\tan u \sec^2 u \cdot u'

Worked examples

Example 1: a power of a polynomial. Outer: u^5. Inner: u = x^2 + 1, u' = 2x:

\frac{d}{dx}\,(x^2 + 1)^5 = 5(x^2 + 1)^4 \cdot 2x = 10x(x^2 + 1)^4

Example 2: trig. Outer: \sin u. Inner: u = 3x:

\frac{d}{dx}\,\sin(3x) = \cos(3x) \cdot 3 = 3\cos(3x)

Example 3: exponential. Outer: e^u. Inner: u = x^2:

\frac{d}{dx}\,e^{x^2} = e^{x^2} \cdot 2x = 2x\,e^{x^2}

Example 4: a square root. Write \sqrt{4x - 1} = (4x - 1)^{1/2}:

\frac{1}{2}(4x - 1)^{-1/2} \cdot 4 = \frac{2}{\sqrt{4x - 1}}

Example 5: logarithm. Outer: \ln u. Inner: u = \cos x:

\frac{d}{dx}\,\ln(\cos x) = \frac{-\sin x}{\cos x} = -\tan x

Example 6: three layers. \sin^2(5x) means [\sin(5x)]^2. Peel from the outside: square, then sine, then 5x:

\frac{d}{dx}\,\sin^2(5x) = 2\sin(5x) \cdot \cos(5x) \cdot 5 = 10\sin(5x)\cos(5x)

How to spot a composition

Ask: "To evaluate this at a number, what would I compute last?" That last operation is the outer function. Everything it acts on is the inner function.

  • (3x + 1)^4: last step is raising to the 4th power. Inner is 3x + 1.
  • e^{\sin x}: last step is e^{(\ )}. Inner is \sin x.
  • \sin x^2 usually means \sin(x^2): inner is x^2. But \sin^2 x means (\sin x)^2: inner is \sin x.

If the inner function is just x, the inner derivative is 1 and the chain rule changes nothing.

Common mistakes

  1. Forgetting the inner derivative. \frac{d}{dx}\,(3x + 1)^4 = 4(3x + 1)^3 \cdot 3, not 4(3x + 1)^3. This is the most common derivative error of all.
  2. Changing the inside. The outer derivative is evaluated at the original inner function: \frac{d}{dx}\sin(x^2) = \cos(x^2) \cdot 2x, not \cos(2x).
  3. Confusing it with the product rule. \sin(x^2) is a composition, while x^2\sin x is a product. See the product rule.
  4. Stopping after one layer. In e^{\sin(2x)} there are three layers, and the answer 2\cos(2x)\,e^{\sin(2x)} needs all three derivatives.

The chain rule is also the engine behind implicit differentiation, related rates and u-substitution. For a longer walkthrough with more practice problems, read the full guide to the chain rule.

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Chain rule: any function

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Frequently asked questions

What is the chain rule in simple terms?

For a function inside another function, take the derivative of the outer function with the inside left as it is, then multiply by the derivative of the inside.

How do you know when to use the chain rule?

Use it whenever a function is applied to something other than plain x, such as (3x+1)^5, \sin(x^2) or e^{4x}. If you would need to compute an inner value first, there is a composition.

What is the chain rule in Leibniz notation?

If y depends on u and u depends on x, then \frac{dy}{dx} = \frac{dy}{du}\cdot\frac{du}{dx}.

How do you use the chain rule more than once?

Peel the layers from the outside in and multiply one derivative per layer. For \sin^2(5x) that gives 2\sin(5x)\cdot\cos(5x)\cdot 5.

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