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AP Calc Unit 7 Review: Differential Equations (AB and BC)

AP Calculus Unit 7 review for AB and BC: slope fields, separation of variables, exponential models, and BC Euler's method and logistic growth.

AP Calculus units Updated 4 min read

At a glance

AB exam weight
5–10%
BC exam weight
5–10%
Big ideas
Slope fields, separation of variables, particular solutions, exponential models
BC only
Euler's method, logistic models
Comes before
Unit 8, applications of integration
On this page
  1. What Unit 7 covers
  2. The key ideas
  3. Sample questions
  4. How to study Unit 7

AP Calculus Unit 7, Differential Equations, puts derivatives and integrals together. A differential equation tells you how a quantity changes, like \frac{dy}{dx} = xy, and your job is to find the quantity itself. It is a smaller unit on the multiple-choice section, but it has its own free-response question on most exams.

AP Calculus AB AP Calculus BC
Exam weight 5–10% 5–10%
Extra topics none Euler's method, logistic models

What Unit 7 covers

College Board splits the unit into these topics. Each row links to a lesson where you can practice it with new numbers every time.

Topic What you learn Practice
Modeling with differential equations Turning "the rate is proportional to" into an equation Growth and decay
Verifying solutions Substituting a function into the equation Separable equations
Sketching slope fields Drawing short segments with slope \frac{dy}{dx} Slope fields
Reasoning with slope fields Matching fields to equations and tracing solutions Slope fields
Euler's method (BC) Stepping along tangent lines to estimate a solution Euler's method
General solutions by separation Separating variables and integrating Separable equations
Particular solutions Using an initial condition to find C Separable equations
Exponential models \frac{dy}{dt} = ky and y = y_0 e^{kt} Growth and decay
Logistic models (BC) Growth that levels off at a carrying capacity Logistic growth

The key ideas

A solution is a function, not a number. To check whether y = Ce^{3x} solves y' = 3y, differentiate: y' = 3Ce^{3x} = 3y. It works for every C, so there is a whole family of solutions. An initial condition picks one.

Slope fields show every solution at once. At each point (x, y), draw a short segment with slope \frac{dy}{dx}. A solution curve follows the segments like a leaf following a current. Where \frac{dy}{dx} depends only on x, segments in the same column are parallel.

Separation of variables solves the equation exactly. Move every y to one side with dy and every x to the other with dx, then integrate both sides.

The particular solution y = 2e^(x²/2)
This curve solves \frac{dy}{dx} = xy with y(0) = 2. Its slope is 0 at x = 0 and grows as x and y grow.

Exponential growth is a differential equation. "The rate of change of y is proportional to y" means \frac{dy}{dt} = ky, and its solutions are y = y_0 e^{kt}. Growth has k > 0, decay has k < 0.

BC: logistic growth levels off. In \frac{dP}{dt} = kP\left(1 - \frac{P}{L}\right), the population approaches the carrying capacity L and grows fastest when P = \frac{L}{2}.

Sample questions

1. Separation of variables. Solve \frac{dy}{dx} = xy with y(0) = 2. Separate and integrate:

\int \frac{1}{y}\,dy = \int x\,dx \quad\Rightarrow\quad \ln|y| = \frac{x^2}{2} + C

At (0, 2), C = \ln 2. Since y > 0, y = 2e^{x^2/2}.

2. Exponential decay. A 100 g sample has a half-life of 5 years. After 15 years, three half-lives have passed, so 100\left(\frac{1}{2}\right)^3 = 12.5 g remain. In the form y = 100e^{kt}, k = -\frac{\ln 2}{5}.

3. Reading a slope field. For \frac{dy}{dx} = x - y, the slope at (1, 0) is 1 and the slope at (2, 2) is 0. Every point on the line y = x has a horizontal segment.

4. BC: Euler's method. For \frac{dy}{dx} = x + y with y(0) = 1, use two steps of size 0.5 to estimate y(1):

Point Slope x + y Next y
(0, 1) 1 1 + 0.5(1) = 1.5
(0.5, 1.5) 2 1.5 + 0.5(2) = 2.5

So y(1) \approx 2.5. The exact solution is y = 2e^x - x - 1, giving y(1) = 2e - 2 \approx 3.44. The solution is concave up, so Euler's method underestimates.

5. BC: logistic model. For \frac{dP}{dt} = 0.2P\left(1 - \frac{P}{500}\right), the carrying capacity is 500 and the population grows fastest when P = 250.

How to study Unit 7

  • Add C the moment you integrate. Adding it after you solve for y gives a wrong family of solutions and loses points.
  • Use the initial condition right away. Plugging in before solving for y often makes the algebra easier.
  • Practice sketching slope fields by hand. The free-response question usually asks you to draw segments at 6 to 9 points.
  • Link back to Unit 5. Questions often ask whether a solution is concave up at a point. Find \frac{d^2y}{dx^2} by differentiating the equation implicitly.
  • Work through problem sets. Try the differential equations practice problems, each with full solutions.

For the full course map, see the AP Calculus AB guide or the AP Calculus BC guide.

AP and Advanced Placement are registered trademarks of College Board, which is not affiliated with PracticeCalculus and does not endorse this guide. Unit names and weights come from College Board's course framework; check it for any changes.

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Frequently asked questions

What is AP Calculus Unit 7 about?

Unit 7 is about equations that involve a derivative. You build differential equations from words, check whether a function is a solution, sketch and read slope fields, solve separable equations with an initial condition, and use exponential growth and decay models.

How much of the AP exam is Unit 7?

Unit 7 is 5 to 10 percent of the multiple-choice score on both AP Calculus AB and BC. A free-response question on slope fields and separation of variables appears on most exams, so it is worth more than its weight suggests.

What is the difference between Unit 7 in AB and BC?

Both courses cover slope fields, separation of variables and exponential models. BC adds Euler's method for approximating solutions and logistic growth models with a carrying capacity.

Why do I lose points when solving separable equations?

The most common reasons are adding +C too late, after solving for y, and forgetting to separate before integrating. Graders give no credit for the rest of a solution that never separates the variables.

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