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Inverse trigonometric functions

Arcsine arcsin(x): Graph, Domain, Range, Derivative and Integral

The arcsine function arcsin(x), the inverse of sine: domain [−1, 1], range [−π/2, π/2], graph, derivative 1/√(1−x²), integral and examples.

Inverse trigonometric functions Updated 3 min read

At a glance

f(x) = \arcsin x = \sin^{-1} x
Domain
[-1, 1]
Range
\left[-\frac{\pi}{2}, \frac{\pi}{2}\right]
Derivative
\frac{1}{\sqrt{1 - x^2}}
Integral
x\arcsin x + \sqrt{1 - x^2} + C
Meaning
The angle in \left[-\frac{\pi}{2}, \frac{\pi}{2}\right] whose sine is x
Symmetry
Odd: \arcsin(-x) = -\arcsin x
On this page
  1. Definition of arcsin x
  2. Graph of y = arcsin x
  3. Key values of arcsine
  4. Properties of arcsine
  5. Derivative of arcsin x
  6. Integrals involving arcsine
  7. Worked examples
  8. Common mistakes
  9. How arcsine connects to other topics

The arcsine function undoes the sine function: \arcsin x is the angle whose sine is x. Because sine repeats, it is not one-to-one, so arcsine picks the single answer in \left[-\frac{\pi}{2}, \frac{\pi}{2}\right]. In calculus it matters mostly as the antiderivative of \frac{1}{\sqrt{1-x^2}}.

Definition of arcsin x

y = \arcsin x \quad\Longleftrightarrow\quad \sin y = x \text{ and } -\frac{\pi}{2} \le y \le \frac{\pi}{2}

So \arcsin\frac{1}{2} = \frac{\pi}{6}, because \sin\frac{\pi}{6} = \frac{1}{2} and \frac{\pi}{6} is in the allowed range. The notation \sin^{-1}x means the same thing.

Graph of y = arcsin x

Graph of y = arcsin x on [−1, 1]
Arcsine rises from -\frac{\pi}{2} at x = -1 to \frac{\pi}{2} at x = 1. The tangent lines at both endpoints are vertical.

The graph is the piece of y = \sin x on \left[-\frac{\pi}{2}, \frac{\pi}{2}\right], reflected across the line y = x.

Key values of arcsine

x -1 -\frac{\sqrt{3}}{2} -\frac{1}{2} 0 \frac{1}{2} \frac{\sqrt{2}}{2} \frac{\sqrt{3}}{2} 1
\arcsin x -\frac{\pi}{2} -\frac{\pi}{3} -\frac{\pi}{6} 0 \frac{\pi}{6} \frac{\pi}{4} \frac{\pi}{3} \frac{\pi}{2}

Properties of arcsine

  • Domain [-1, 1], range \left[-\frac{\pi}{2}, \frac{\pi}{2}\right]. Inputs outside [-1, 1] are undefined, since no angle has sine 2.
  • Increasing. Arcsine is strictly increasing on its whole domain.
  • Odd. \arcsin(-x) = -\arcsin x.
  • Cancellation. \sin(\arcsin x) = x for every x in [-1, 1], but \arcsin(\sin x) = x only for x in \left[-\frac{\pi}{2}, \frac{\pi}{2}\right].
  • Relation to arccosine. \arcsin x + \arccos x = \frac{\pi}{2}. See arccosine.

Derivative of arcsin x

\frac{d}{dx}\arcsin x = \frac{1}{\sqrt{1 - x^2}}, \qquad -1 < x < 1

Why. Let y = \arcsin x, so \sin y = x. Implicit differentiation gives \cos y \cdot y' = 1, so y' = \frac{1}{\cos y}. Since y is in \left[-\frac{\pi}{2}, \frac{\pi}{2}\right], \cos y \ge 0, and \cos y = \sqrt{1 - \sin^2 y} = \sqrt{1 - x^2}. This is a special case of the inverse function rule.

At x = \pm 1 the denominator is zero, which is why the graph has vertical tangents at its endpoints.

Integrals involving arcsine

The derivative formula, read backward, is the integral you will use most:

\int \frac{dx}{\sqrt{1 - x^2}} = \arcsin x + C, \qquad \int \frac{dx}{\sqrt{a^2 - x^2}} = \arcsin\frac{x}{a} + C \ (a > 0)

The integral of arcsine itself comes from integration by parts with u = \arcsin x, dv = dx:

\int \arcsin x\,dx = x\arcsin x - \int\frac{x}{\sqrt{1-x^2}}\,dx = x\arcsin x + \sqrt{1 - x^2} + C

Worked examples

Example 1: chain rule. Differentiate f(x) = \arcsin(3x):

f'(x) = \frac{3}{\sqrt{1 - 9x^2}}

Example 2: a definite integral. \int_0^{1/2}\frac{dx}{\sqrt{1-x^2}} = \arcsin\frac{1}{2} - \arcsin 0 = \frac{\pi}{6}.

Example 3: using a. \int\frac{dx}{\sqrt{9 - x^2}} = \arcsin\frac{x}{3} + C.

Example 4: composition. Simplify \cos(\arcsin x). If \theta = \arcsin x then \sin\theta = x and \cos\theta \ge 0, so \cos(\arcsin x) = \sqrt{1 - x^2}.

Common mistakes

  1. Reading \sin^{-1}x as \frac{1}{\sin x}. The reciprocal is \csc x, covered on reciprocal trig functions.
  2. Giving an angle outside the range. \arcsin\left(-\frac{1}{2}\right) = -\frac{\pi}{6}, not \frac{7\pi}{6} or \frac{11\pi}{6}.
  3. Plugging in |x| > 1. \arcsin 2 does not exist as a real number.
  4. Forgetting the chain rule factor. \frac{d}{dx}\arcsin(x^2) = \frac{2x}{\sqrt{1 - x^4}}, not \frac{1}{\sqrt{1-x^4}}.

How arcsine connects to other topics

Arcsine is the backbone of the substitution x = a\sin\theta in trig substitution, used for integrals with \sqrt{a^2 - x^2}. Its siblings are arccosine and arctangent, and all three derivatives are derived the same way in the guide to implicit differentiation.

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Frequently asked questions

What is the derivative of arcsin x?

The derivative of \arcsin x is \frac{1}{\sqrt{1-x^2}} for -1 < x < 1. With the chain rule, \frac{d}{dx}\arcsin(u) = \frac{u'}{\sqrt{1-u^2}}.

What is the domain and range of arcsin x?

The domain is [-1, 1], because sine only produces values in that interval. The range is \left[-\frac{\pi}{2}, \frac{\pi}{2}\right], the interval on which sine is one-to-one.

Is sin inverse the same as 1/sin x?

No. \sin^{-1}x is the inverse function arcsine. The reciprocal \frac{1}{\sin x} is the cosecant, \csc x.

What is the integral of arcsin x?

Using integration by parts with u = \arcsin x and dv = dx gives \int\arcsin x\,dx = x\arcsin x + \sqrt{1-x^2} + C.

Why is arcsin(sin x) not always equal to x?

Arcsine always returns an angle between -\frac{\pi}{2} and \frac{\pi}{2}. For example \arcsin(\sin\pi) = \arcsin 0 = 0, not \pi.

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