Arcsine arcsin(x): Graph, Domain, Range, Derivative and Integral
The arcsine function arcsin(x), the inverse of sine: domain [−1, 1], range [−π/2, π/2], graph, derivative 1/√(1−x²), integral and examples.
Inverse trigonometric functions Updated 3 min read
At a glance
- Domain
- [-1, 1]
- Range
- \left[-\frac{\pi}{2}, \frac{\pi}{2}\right]
- Derivative
- \frac{1}{\sqrt{1 - x^2}}
- Integral
- x\arcsin x + \sqrt{1 - x^2} + C
- Meaning
- The angle in \left[-\frac{\pi}{2}, \frac{\pi}{2}\right] whose sine is x
- Symmetry
- Odd: \arcsin(-x) = -\arcsin x
On this page
The arcsine function undoes the sine function: \arcsin x is the angle whose sine is x. Because sine repeats, it is not one-to-one, so arcsine picks the single answer in \left[-\frac{\pi}{2}, \frac{\pi}{2}\right]. In calculus it matters mostly as the antiderivative of \frac{1}{\sqrt{1-x^2}}.
Definition of arcsin x
So \arcsin\frac{1}{2} = \frac{\pi}{6}, because \sin\frac{\pi}{6} = \frac{1}{2} and \frac{\pi}{6} is in the allowed range. The notation \sin^{-1}x means the same thing.
Graph of y = arcsin x
The graph is the piece of y = \sin x on \left[-\frac{\pi}{2}, \frac{\pi}{2}\right], reflected across the line y = x.
Key values of arcsine
| x | -1 | -\frac{\sqrt{3}}{2} | -\frac{1}{2} | 0 | \frac{1}{2} | \frac{\sqrt{2}}{2} | \frac{\sqrt{3}}{2} | 1 |
|---|---|---|---|---|---|---|---|---|
| \arcsin x | -\frac{\pi}{2} | -\frac{\pi}{3} | -\frac{\pi}{6} | 0 | \frac{\pi}{6} | \frac{\pi}{4} | \frac{\pi}{3} | \frac{\pi}{2} |
Properties of arcsine
- Domain [-1, 1], range \left[-\frac{\pi}{2}, \frac{\pi}{2}\right]. Inputs outside [-1, 1] are undefined, since no angle has sine 2.
- Increasing. Arcsine is strictly increasing on its whole domain.
- Odd. \arcsin(-x) = -\arcsin x.
- Cancellation. \sin(\arcsin x) = x for every x in [-1, 1], but \arcsin(\sin x) = x only for x in \left[-\frac{\pi}{2}, \frac{\pi}{2}\right].
- Relation to arccosine. \arcsin x + \arccos x = \frac{\pi}{2}. See arccosine.
Derivative of arcsin x
Why. Let y = \arcsin x, so \sin y = x. Implicit differentiation gives \cos y \cdot y' = 1, so y' = \frac{1}{\cos y}. Since y is in \left[-\frac{\pi}{2}, \frac{\pi}{2}\right], \cos y \ge 0, and \cos y = \sqrt{1 - \sin^2 y} = \sqrt{1 - x^2}. This is a special case of the inverse function rule.
At x = \pm 1 the denominator is zero, which is why the graph has vertical tangents at its endpoints.
Integrals involving arcsine
The derivative formula, read backward, is the integral you will use most:
The integral of arcsine itself comes from integration by parts with u = \arcsin x, dv = dx:
Worked examples
Example 1: chain rule. Differentiate f(x) = \arcsin(3x):
Example 2: a definite integral. \int_0^{1/2}\frac{dx}{\sqrt{1-x^2}} = \arcsin\frac{1}{2} - \arcsin 0 = \frac{\pi}{6}.
Example 3: using a. \int\frac{dx}{\sqrt{9 - x^2}} = \arcsin\frac{x}{3} + C.
Example 4: composition. Simplify \cos(\arcsin x). If \theta = \arcsin x then \sin\theta = x and \cos\theta \ge 0, so \cos(\arcsin x) = \sqrt{1 - x^2}.
Common mistakes
- Reading \sin^{-1}x as \frac{1}{\sin x}. The reciprocal is \csc x, covered on reciprocal trig functions.
- Giving an angle outside the range. \arcsin\left(-\frac{1}{2}\right) = -\frac{\pi}{6}, not \frac{7\pi}{6} or \frac{11\pi}{6}.
- Plugging in |x| > 1. \arcsin 2 does not exist as a real number.
- Forgetting the chain rule factor. \frac{d}{dx}\arcsin(x^2) = \frac{2x}{\sqrt{1 - x^4}}, not \frac{1}{\sqrt{1-x^4}}.
How arcsine connects to other topics
Arcsine is the backbone of the substitution x = a\sin\theta in trig substitution, used for integrals with \sqrt{a^2 - x^2}. Its siblings are arccosine and arctangent, and all three derivatives are derived the same way in the guide to implicit differentiation.
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